## Summary

To get a real date from day number, or "nth day of year" you can use the DATE function.

In the example shown, the formula in C5 is:

``````=DATE(2015,1,B5)
``````

## Generic formula

``=DATE(year,1,daynum)``

## Explanation

The DATE function build dates from separate year, month, and day values. One of it's tricks is the ability to roll forward to correct dates when given days and months that are "out of range".

For example, DATE returns April 9, 2016 with the following arguments:

``````=DATE(2016,1,100)
``````

There is no 100th day in January, so DATE simple moves forward 100 days from January 1 and figures returns the correct date.

The formula on this page takes advantage of this behavior. The year assumed to be 2015 in this case, so 2015 is hard-coded for year, and 1 is used for month. The day value comes from column B, and the DATE function calculates the date as explained above.

### Extracting a year value from a Julian date

If you have a date in a Julian format, for example, 10015, where the format is "dddyy", you can adapt the formula as follows:

``````=DATE(RIGHT(A1,2),1,LEFT(A1,3))
``````

Here, we use RIGHT to extract the 2 characters from the right for year, and LEFT to extract 3 characters from the left for day. Month is supplied as 1, like the first example. Author ### Dave Bruns

Hi - I'm Dave Bruns, and I run Exceljet with my wife, Lisa. Our goal is to help you work faster in Excel. We create short videos, and clear examples of formulas, functions, pivot tables, conditional formatting, and charts.